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Summary
Description 
English: Simplified version of similar triangles proof for Pythagoras' theorem.
In triangle ACB, angle ACB is the right angle. CH is a perpendicular on hypotenuse AB of triangle ACB. In triangle AHC and triangle ACB, ∠AHC=∠ACB as each is a right angle. ∠HAC=∠CAB as they are common angles at vertex A. Thus triangle AHC is similar to triangle ACB by AA test. Thus,
In triangle BHC and triangle ACB, ∠BHC=∠ACB as each is a right angle. ∠HBC=∠CBA as they are common angles at vertex B. Thus triangle BHC is similar to triangle BCA by AA test. Thus,
which is the Pythagoras theorem.

Date 
20120515 10:08 (UTC) 
Source 
This file was derived from:
Reference: ^{}
 ↑ (2011) GEOMETRY Standard X, Secretary, Maharashtra State Board of Secondary and Higher Secondary Education, Pune411 004, pp. 22, 23

Author 
 derivative work: Gauravjuvekar
 derivative work: Gauravjuvekar


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